char * strcat ( char * destination, const char * source ); null-character is included at the end of the new string formed by the concatenation of both in destination.I need to concatenate two const chars like these: const char *one. In your example one and two are char pointers, pointing to char constants.In C++, use std::string , and the operator+ , it is designed specifically to solve problems like this. #include <iostream> #include <string> using . I would guess that i would need to allocate memory to totalLine? Yes, you guessed correctly. totalLine is an uninitialized pointer, so those strcpy calls . 1. const char* p=new char[strlen(metadata.getRoot())+strlen(metadata.getPath()) +1];. the length plus 1 to store '\0'. 2.string a = "hello "; const char *b = "world"; a += b; const char *C = a.c_str();. or without modifying a : string a = "hello "; const char *b = "world"; string c . Instead of using a plain char string, you should use the string library provided by the C++ library: #include <string> #include <iostream> using . How to concat two char* string in C program. .. How do you set, clear and toggle a single bit in C/C++? 6 · Cannot modify C string · 1655.Remove those char * ret declarations inside if blocks which hide outer ret . Therefor you have memory leak and on the other hand un-allocated . Are you aware of existence of std::string ? It's a class that handles strings in C++; char * is legacy from C. std::string provides + operator, that does .

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char * strcat ( char * destination, const char * source ); null-character is included at the end of the new string formed by the concatenation of both in destination.I need to concatenate two const chars like these: const char *one. In your example one and two are char pointers, pointing to char constants.In C++, use std::string , and the operator+ , it is designed specifically to solve problems like this. #include <iostream> #include <string> using . I would guess that i would need to allocate memory to totalLine? Yes, you guessed correctly. totalLine is an uninitialized pointer, so those strcpy calls . 1. const char* p=new char[strlen(metadata.getRoot())+strlen(metadata.getPath()) +1];. the length plus 1 to store '\0'. 2.string a = "hello "; const char *b = "world"; a += b; const char *C = a.c_str();. or without modifying a : string a = "hello "; const char *b = "world"; string c . Instead of using a plain char string, you should use the string library provided by the C++ library: #include <string> #include <iostream> using . How to concat two char* string in C program. .. How do you set, clear and toggle a single bit in C/C++? 6 · Cannot modify C string · 1655.Remove those char * ret declarations inside if blocks which hide outer ret . Therefor you have memory leak and on the other hand un-allocated . Are you aware of existence of std::string ? It's a class that handles strings in C++; char * is legacy from C. std::string provides + operator, that does .

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char * strcat ( char * destination, const char * source ); null-character is included at the end of the new string formed by the concatenation of both in destination.I need to concatenate two const chars like these: const char *one. In your example one and two are char pointers, pointing to char constants.In C++, use std::string , and the operator+ , it is designed specifically to solve problems like this. #include <iostream> #include <string> using . I would guess that i would need to allocate memory to totalLine? Yes, you guessed correctly. totalLine is an uninitialized pointer, so those strcpy calls . 1. const char* p=new char[strlen(metadata.getRoot())+strlen(metadata.getPath()) +1];. the length plus 1 to store '\0'. 2.string a = "hello "; const char *b = "world"; a += b; const char *C = a.c_str();. or without modifying a : string a = "hello "; const char *b = "world"; string c . Instead of using a plain char string, you should use the string library provided by the C++ library: #include <string> #include <iostream> using . How to concat two char* string in C program. .. How do you set, clear and toggle a single bit in C/C++? 6 · Cannot modify C string · 1655.Remove those char * ret declarations inside if blocks which hide outer ret . Therefor you have memory leak and on the other hand un-allocated . Are you aware of existence of std::string ? It's a class that handles strings in C++; char * is legacy from C. std::string provides + operator, that does .

char * strcat ( char * destination, const char * source ); null-character is included at the end of the new string formed by the concatenation of both in destination.I need to concatenate two const chars like these: const char *one. In your example one and two are char pointers, pointing to char constants.In C++, use std::string , and the operator+ , it is designed specifically to solve problems like this. #include <iostream> #include <string> using . I would guess that i would need to allocate memory to totalLine? Yes, you guessed correctly. totalLine is an uninitialized pointer, so those strcpy calls . 1. const char* p=new char[strlen(metadata.getRoot())+strlen(metadata.getPath()) +1];. the length plus 1 to store '\0'. 2.string a = "hello "; const char *b = "world"; a += b; const char *C = a.c_str();. or without modifying a : string a = "hello "; const char *b = "world"; string c . Instead of using a plain char string, you should use the string library provided by the C++ library: #include <string> #include <iostream> using . How to concat two char* string in C program. .. How do you set, clear and toggle a single bit in C/C++? 6 · Cannot modify C string · 1655.Remove those char * ret declarations inside if blocks which hide outer ret . Therefor you have memory leak and on the other hand un-allocated . Are you aware of existence of std::string ? It's a class that handles strings in C++; char * is legacy from C. std::string provides + operator, that does .

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char * strcat ( char * destination, const char * source ); null-character is included at the end of the new string formed by the concatenation of both in destination.I need to concatenate two const chars like these: const char *one. In your example one and two are char pointers, pointing to char constants.In C++, use std::string , and the operator+ , it is designed specifically to solve problems like this. #include <iostream> #include <string> using . I would guess that i would need to allocate memory to totalLine? Yes, you guessed correctly. totalLine is an uninitialized pointer, so those strcpy calls . 1. const char* p=new char[strlen(metadata.getRoot())+strlen(metadata.getPath()) +1];. the length plus 1 to store '\0'. 2.string a = "hello "; const char *b = "world"; a += b; const char *C = a.c_str();. or without modifying a : string a = "hello "; const char *b = "world"; string c . Instead of using a plain char string, you should use the string library provided by the C++ library: #include <string> #include <iostream> using . How to concat two char* string in C program. .. How do you set, clear and toggle a single bit in C/C++? 6 · Cannot modify C string · 1655.Remove those char * ret declarations inside if blocks which hide outer ret . Therefor you have memory leak and on the other hand un-allocated . Are you aware of existence of std::string ? It's a class that handles strings in C++; char * is legacy from C. std::string provides + operator, that does .

char * strcat ( char * destination, const char * source ); null-character is included at the end of the new string formed by the concatenation of both in destination.I need to concatenate two const chars like these: const char *one. In your example one and two are char pointers, pointing to char constants.In C++, use std::string , and the operator+ , it is designed specifically to solve problems like this. #include <iostream> #include <string> using . I would guess that i would need to allocate memory to totalLine? Yes, you guessed correctly. totalLine is an uninitialized pointer, so those strcpy calls . 1. const char* p=new char[strlen(metadata.getRoot())+strlen(metadata.getPath()) +1];. the length plus 1 to store '\0'. 2.string a = "hello "; const char *b = "world"; a += b; const char *C = a.c_str();. or without modifying a : string a = "hello "; const char *b = "world"; string c . Instead of using a plain char string, you should use the string library provided by the C++ library: #include <string> #include <iostream> using . How to concat two char* string in C program. .. How do you set, clear and toggle a single bit in C/C++? 6 · Cannot modify C string · 1655.Remove those char * ret declarations inside if blocks which hide outer ret . Therefor you have memory leak and on the other hand un-allocated . Are you aware of existence of std::string ? It's a class that handles strings in C++; char * is legacy from C. std::string provides + operator, that does .

char * strcat ( char * destination, const char * source ); null-character is included at the end of the new string formed by the concatenation of both in destination.I need to concatenate two const chars like these: const char *one. In your example one and two are char pointers, pointing to char constants.In C++, use std::string , and the operator+ , it is designed specifically to solve problems like this. #include <iostream> #include <string> using . I would guess that i would need to allocate memory to totalLine? Yes, you guessed correctly. totalLine is an uninitialized pointer, so those strcpy calls . 1. const char* p=new char[strlen(metadata.getRoot())+strlen(metadata.getPath()) +1];. the length plus 1 to store '\0'. 2.string a = "hello "; const char *b = "world"; a += b; const char *C = a.c_str();. or without modifying a : string a = "hello "; const char *b = "world"; string c . Instead of using a plain char string, you should use the string library provided by the C++ library: #include <string> #include <iostream> using . How to concat two char* string in C program. .. How do you set, clear and toggle a single bit in C/C++? 6 · Cannot modify C string · 1655.Remove those char * ret declarations inside if blocks which hide outer ret . Therefor you have memory leak and on the other hand un-allocated . Are you aware of existence of std::string ? It's a class that handles strings in C++; char * is legacy from C. std::string provides + operator, that does .

char * strcat ( char * destination, const char * source ); null-character is included at the end of the new string formed by the concatenation of both in destination.I need to concatenate two const chars like these: const char *one. In your example one and two are char pointers, pointing to char constants.In C++, use std::string , and the operator+ , it is designed specifically to solve problems like this. #include <iostream> #include <string> using . I would guess that i would need to allocate memory to totalLine? Yes, you guessed correctly. totalLine is an uninitialized pointer, so those strcpy calls . 1. const char* p=new char[strlen(metadata.getRoot())+strlen(metadata.getPath()) +1];. the length plus 1 to store '\0'. 2.string a = "hello "; const char *b = "world"; a += b; const char *C = a.c_str();. or without modifying a : string a = "hello "; const char *b = "world"; string c . Instead of using a plain char string, you should use the string library provided by the C++ library: #include <string> #include <iostream> using . How to concat two char* string in C program. .. How do you set, clear and toggle a single bit in C/C++? 6 · Cannot modify C string · 1655.Remove those char * ret declarations inside if blocks which hide outer ret . Therefor you have memory leak and on the other hand un-allocated . Are you aware of existence of std::string ? It's a class that handles strings in C++; char * is legacy from C. std::string provides + operator, that does .

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char * strcat ( char * destination, const char * source ); null-character is included at the end of the new string formed by the concatenation of both in destination.I need to concatenate two const chars like these: const char *one. In your example one and two are char pointers, pointing to char constants.In C++, use std::string , and the operator+ , it is designed specifically to solve problems like this. #include <iostream> #include <string> using . I would guess that i would need to allocate memory to totalLine? Yes, you guessed correctly. totalLine is an uninitialized pointer, so those strcpy calls . 1. const char* p=new char[strlen(metadata.getRoot())+strlen(metadata.getPath()) +1];. the length plus 1 to store '\0'. 2.string a = "hello "; const char *b = "world"; a += b; const char *C = a.c_str();. or without modifying a : string a = "hello "; const char *b = "world"; string c . Instead of using a plain char string, you should use the string library provided by the C++ library: #include <string> #include <iostream> using . How to concat two char* string in C program. .. How do you set, clear and toggle a single bit in C/C++? 6 · Cannot modify C string · 1655.Remove those char * ret declarations inside if blocks which hide outer ret . Therefor you have memory leak and on the other hand un-allocated . Are you aware of existence of std::string ? It's a class that handles strings in C++; char * is legacy from C. std::string provides + operator, that does .

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